Herbert Grasemann III

[garykevinware]

Here is another problem of Herbert Grasemann, courtesy of Guy Meissonnier.



Herbert Grasemann Schachmaty w SSR 1961 First Prize Dedicated to Lew Loschinski #11

Guy Meissonnier said that the Grasemann mate in 14 that we presented two weeks ago, under Herbert Grasemann, has been shown by Rybka 3 to have a short mate in 12.
"For the problem in 14 moves, here is Rybka 3' solution : 1 Rd5 1...Kc3 2 Rc8+ 2...Kb4 3 Rd7 3...Be3 4 Rb7+ 4...Bb6 5 RxBb6 + 5...Ka5 6 Rb3 6...Rh1+ 7 Kg5 7...Rh6 8 KxRh6 8...Rh1+ 9 Bh5 9...Ka4 10 Rb7 10...Rxh5+ 11 KxRh5 11...b2-b1=Q and 12 Ra8 mate." After 1 Rd5 1...Kc3 2 Rc8+, if 2...Kd2, 3 Kg3 3...Ke1 4 Rd5xd3 (with the threat 5 Rd1 mate) 4...Bc1-h6 (in order to take the control of the square f8 and in order to prevent Rc8-h8 and Rh8-h1+), but 5 Kg2, and mate in 2 more moves.
Guy Meissonnier also sent me a link to an online chess encyclopedia: http://www.echesspedia.com
11 points for sending me a complete variation to this week's problem, at garykevinware@yahoo.com , by next Wednesday.

[garykevinware]

Here is the answer to last week's problem:
Grasemann #11-
"Without the white pawn on e2, there is a mate in one move by 1 Ba7xRf2 mate but 1 e2-e3? 1...Rf2xRd2! and 2 e3-e4+ 2...Rd2-f2! (switchback). So we play first 1 d3-d4! 1...Rf2-f1 2 d4-d5+ 2...Rf1-f2 and now 3 Rd2-d4! 3...Rf2-f1! 4 Rd4-b4+!! (and not 4 Rd4-a4+?? 4...Rf1-f2 5 e2-e3 5...Rf2xf3! 6 e3-e4+ Rf3-f2 7 Ra4-d4 but 7...Rf2xf4+!! (and not 7..Rf2-f1?? 8 Rd4-d2+! Rf1-f2 and 9 Ba7xRf2 mate) 4...Rf1-f2 5 Rb2-b6!! 5...Rf2xf3 6 Rb6-a6+! (in order to protect the bishop at a7) 6...Rf3-f2 7 e2-e3! 7...Rf2-f1! (and not 7...Rf2xf4+?? 8 e3xRf4 mate) 8 e3-e4+ Rf1-f2 9 Ra6-b6!! 9...Rf2-f1 (or 9...Rf1xf4+ 10 Rb6-f6+ 10...Rf4-f2 and 11 Ba7xRf2 mate) 10 Rb6-Rb2 + Rf1-f2 and 11 Ba7xRf2 mate. (if 9...Rf2-a2 10 Rb6-b2 + 10...Ra2xBa7 and 11 Rb2-g2 mate (11 Nf3#))."
"Four direct foreplans followed each other in logical sequence! A beautiful chess nut for your pleasure!"
Guy Meissonnier also sent me another problem based on Grasemann's mate in 11.



Stefan EISERT and Hans-Peter REHM (source SCHACH-AKTIV 2003 First Prize) Version of the problem of GRASEMANN in 11 moves.
White to play and mate in 10 moves.

Solution: 1 Be3-a7! 1...h7-h5 2 Rd2-d4! 2..Rf2-f1 3 Rd4-d6+ 3...Rf1-f2 4 Rd6-b6! 4...Rf2-f1 5 Rb6-a6+ 5...Rf1-f2
6 e2-e3! Rf2-f1 ! 7 e3-e4+ 7...Rf1-f2 8 Ra6-b6!! 8...Rf2xf4+ (or 8...Rf2-a2 9 Rb6-b2+ 9...Ra2xBa7 10 Rb2-g2 mate.) 9 Rb6-f6+
9...Rf4-f2 and 10 Rf6xRf2 mate.